-16x^2-200x-600=0

Solution for -16x^2-200x-600=0 equation:

-16x^2-200x-600=0

a = -16; b = -200; c = -600;
Δ = b2-4ac
Δ = -2002-4·(-16)·(-600)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-40}{2*-16}=\frac{160}{-32}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+40}{2*-16}=\frac{240}{-32}
=-7+1/2
$